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Version 3
Last scraped
Edited on 23/04/2025, 12:04:17 UTC
Ecco il LaTeX corretto:
f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}
Code:
f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}
Version 2
Edited on 16/04/2025, 12:33:56 UTC
Ecco il LaTeX corretto:
\[f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}\]
f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}
Code:
f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}
Version 1
Scraped on 16/04/2025, 12:09:08 UTC
Code:
\[f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}\]
Original archived Re: Un modello logistico del prezzo di Bitcoin
Scraped on 16/04/2025, 12:03:57 UTC
Trovato ecco il LaTeX corretto:
Code:
\[f(x)= L_L + (L_U - L_L) \cdot (e^{(\frac{S}{L_U - L_L} (I_{x} - x) + c (e^{c} + 1)^{-(e^{c} + 1) e^{- c}}) (e^{c} + 1)^{(e^{c} + 1) e^{- c}}} + 1)^{- e^{- c}}\]