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Scraped on 05/05/2025, 09:16:09 UTC
You can see here also that Y number for puzzle 69 is low
You're computing a number that is simply Y = sqrt(X) * 8192.
Where X is the normalized key position (from 0 to 1) in the puzzle space. What am I missing?
Original archived Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Scraped on 05/05/2025, 09:11:02 UTC
You can see here also that Y number for puzzle 69 is low
You're computing a number that is simply sqrt(X) * 8192.
Where X is the normalized key position (from 0 to 1) in the puzzle space. What am I missing?