Ninjastic
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Version 2
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Edited on 15/05/2025, 12:22:07 UTC
Quote from: XXONE on May 08, 2025, 11:54:52 AM
Even if you have one phrase of 12 words in a chaotic order, then the enumeration will take 8916100448256 options. This is unrealistic, you need to remember your scheme, there is no other way.
The number 8916100448256 is 224 * 312.
You did 1212 = 8916100448256. That has nothing to do with's a lot more than the number of possible combinations you can make with 12 words, which is 12! = 479001600. Brute-forcing a seed phrase out of 12 correct but randomized words is not impossible.

To explain this to yourself: try it with 3 words:
A B C
A C B
B A C
B C A
C A B
C B A
That's not 33 = 9 combinations, it's 3! = 1 * 2 * 3 = 6 combinations.
Version 1
Scraped on 08/05/2025, 12:27:24 UTC
Quote from: XXONE on May 08, 2025, 11:54:52 AM
Even if you have one phrase of 12 words in a chaotic order, then the enumeration will take 8916100448256 options. This is unrealistic, you need to remember your scheme, there is no other way.
The number 8916100448256 is 224x3 * 312. That has nothing to do with the number of possible combinations you can make with 12 words:, which is 12! = 479001600. Brute-forcing a seed phrase out of 12 correct but randomized words is not impossible.
Original archived Re: Seed phrase recovery?
Scraped on 08/05/2025, 12:22:07 UTC
Quote from: XXONE on May 08, 2025, 11:54:52 AM
Even if you have one phrase of 12 words in a chaotic order, then the enumeration will take 8916100448256 options. This is unrealistic, you need to remember your scheme, there is no other way.
The number 8916100448256 is 224x312. That has nothing to do with the number of possible combinations you can make with 12 words: 12! = 479001600. Brute-forcing a seed phrase out of 12 correct but randomized words is not impossible.