Next scheduled rescrape ... never
Version 1
Last scraped
Scraped on 27/08/2025, 10:20:46 UTC
Hi all.
Px = 80761252842007823267676923098838519533867178259061318285796836088556437370050
Py = 10738555717992617802285220494903845365923729217029449460443518382927240297340
Ax = 93560427823998350675410474831001446736200963751037120112392597322455167739793
Ay = 93848508593538492915520554344759249877309109996279289133143629759880647227979
Bx = 50213163450946219488224773860514757649033909603552708244598159315971281928720
By = 93848508593538492915520554344759249877309109996279289133143629759880647227979
A-B=P
Points A and B have a common Y coordinate. For each point P on the curve, there is a pair of points A and B such that A-B=P. Does this give us an advantage when computing the private key?
P.S. Sorry for my English
Px = 80761252842007823267676923098838519533867178259061318285796836088556437370050
Py = 10738555717992617802285220494903845365923729217029449460443518382927240297340
Ax = 93560427823998350675410474831001446736200963751037120112392597322455167739793
Ay = 93848508593538492915520554344759249877309109996279289133143629759880647227979
Bx = 50213163450946219488224773860514757649033909603552708244598159315971281928720
By = 93848508593538492915520554344759249877309109996279289133143629759880647227979
A-B=P
Points A and B have a common Y coordinate. For each point P on the curve, there is a pair of points A and B such that A-B=P. Does this give us an advantage when computing the private key?
P.S. Sorry for my English
Original archived P = A[X1, Y] - B[X2,Y]
Scraped on 27/08/2025, 10:15:15 UTC
Hi all.
Px = 80761252842007823267676923098838519533867178259061318285796836088556437370050
Py = 10738555717992617802285220494903845365923729217029449460443518382927240297340
Ax = 93560427823998350675410474831001446736200963751037120112392597322455167739793
Ay = 93848508593538492915520554344759249877309109996279289133143629759880647227979
Bx = 50213163450946219488224773860514757649033909603552708244598159315971281928720
By = 93848508593538492915520554344759249877309109996279289133143629759880647227979
A-B=P
Points A and B have a common Y coordinate. For each point P on the curve, there is a pair of points A and B such that A-B=P. Does this give us an advantage when computing the private key?
P.S. Sorry for my English
Px = 80761252842007823267676923098838519533867178259061318285796836088556437370050
Py = 10738555717992617802285220494903845365923729217029449460443518382927240297340
Ax = 93560427823998350675410474831001446736200963751037120112392597322455167739793
Ay = 93848508593538492915520554344759249877309109996279289133143629759880647227979
Bx = 50213163450946219488224773860514757649033909603552708244598159315971281928720
By = 93848508593538492915520554344759249877309109996279289133143629759880647227979
A-B=P
Points A and B have a common Y coordinate. For each point P on the curve, there is a pair of points A and B such that A-B=P. Does this give us an advantage when computing the private key?
P.S. Sorry for my English