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Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
Satoshis are floating back to 1FLAMEN6 now... .
Still not at least some hints. Hope this will not become a farce.
I noticed them too Still not at least some hints. Hope this will not become a farce.
when I checked the exact emptying time.I wonder what is it from? Anyway, they are worth 10USD now so nothing particularly rewarding.
I wanted to ask, did you have a bot or whatever observing that address? Your post that it was emptied was very well timed too
Just a guess --
If you follow the transaction trail back, those coins came from an address that withdrew the coins in the first place. I wonder if this is just the solver demonstrating to someone (the MB writer?) that he has control of the address.
It went:
1FLAMEN6rq2BqMnkUmsJBqCGWdwgVKcegd --> 15x25pXex9ZFUr4kAkTL9ayPCap7VLW8Vx
15x25pXex9ZFUr4kAkTL9ayPCap7VLW8Vx --> 1PGfmyE8ZS6WVNH64wXMtHQwsQRwu5widH
1PGfmyE8ZS6WVNH64wXMtHQwsQRwu5widH --> 1L7dZK3FPCN75VBdHurfF7tZnzqbo5TWYt
1L7dZK3FPCN75VBdHurfF7tZnzqbo5TWYt --> 1FLAMEN6rq2BqMnkUmsJBqCGWdwgVKcegd
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
Looks like it will be next week before we get the solution:
https://twitter.com/DMOberhaus/status/959430798930776064
:
Congratulations to YuTü.Co.in (or whoever it was)!
https://twitter.com/DMOberhaus/status/959430798930776064
:
Quote
@DMOberhaus:
Currently speaking with the person who solved it, and their solution was pretty genius. The write-up will be published early next week.
Currently speaking with the person who solved it, and their solution was pretty genius. The write-up will be published early next week.
Congratulations to YuTü.Co.in (or whoever it was)!
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
Another observation re: data.
If you look at the first 17 bits of the inner track top color (l->r) against the first 17 bits of the outer track top color in same direction, they are identical. I know you'd expect repeats even in random data but 17 bits in a row starting right on the boundary? Odds are 1 in 131072 that'd happen?
inside colors
"000101010010110110", // outside track top, left to right
outside colors
"0001010100101101110010110000", // inside track top, left to right
If you look at the first 17 bits of the inner track top color (l->r) against the first 17 bits of the outer track top color in same direction, they are identical. I know you'd expect repeats even in random data but 17 bits in a row starting right on the boundary? Odds are 1 in 131072 that'd happen?
inside colors
"000101010010110110", // outside track top, left to right
outside colors
"0001010100101101110010110000", // inside track top, left to right
Just to add to this: I've run comparisons between every string of inner and outer flames, reversed and flipped (exchanging 1s and 0s), and no other strings match up their first bits like this. Most comparisons match only 0, and the most any other pair of strings matches up, is 7. (Also note, the script double-counts, since every permutation flips one of the strings.)
0: 448 (0 characters matched at the beginning of the string)
1: 230
2: 91
3: 65
4: 33
5: 17
6: 8
7: 2
8: 0
9: 0
10: 0
11: 0
12: 0
13: 0
14: 0
15: 0
16: 0
17: 2
Could be a coincidence, but the 17 really stands out.
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
Another observation re: data.
If you look at the first 17 bits of the inner track top color (l->r) against the first 17 bits of the outer track top color in same direction, they are identical. I know you'd expect repeats even in random data but 17 bits in a row starting right on the boundary? Odds are 1 in 131072 that'd happen?
inside colors
"000101010010110110", // outside track top, left to right
outside colors
"0001010100101101110010110000", // inside track top, left to right
+ 17 leaves
If you look at the first 17 bits of the inner track top color (l->r) against the first 17 bits of the outer track top color in same direction, they are identical. I know you'd expect repeats even in random data but 17 bits in a row starting right on the boundary? Odds are 1 in 131072 that'd happen?
inside colors
"000101010010110110", // outside track top, left to right
outside colors
"0001010100101101110010110000", // inside track top, left to right
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
guys, I would hate to cool your optimism down, but of course you realize that every second binary digit (5 of them coding every baconian letter) belongs to that crazy 0x1x1x pattern that is constant throughout the flames. It can't imagine the creator choosing letters and wording so carefullty, so that she can convey her intended message but chosen letters would not break the constant pattern.
They've been able to encode information into bitcoin public addresses (i.e., the snow poem). It's probably not beyond their capabilities to construct an arbitrary bitstream (and keep in mind, we're only talking about just the flame heights here) with enough sophistication to encode something else.
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On the other hand, it makes much sense what RealOnTheMF said, that it is a massive coincidence: doing the exhaustive search of all possible permutations of all subsets of 8 flame segments, accepting CW or CCW order of each segment, skipping every 1 flame or 2 or 3 or 4 or 5 or whatever threshold he chose as the upper limit, applying the 011010 XOR or not, excluding first k flames when applying the XOR (k=0,1,etc.) ...
I agree -- I believe this is really just a coincidence. But there must be a methodology for deciphering all these 1s and 0s, and so far, no one appears to have had much luck in getting a foothold on it. It's interesting, and it's worth exploring.
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
It was my belief that the message properly decoded would read "thecolouriskeyfile", which would indicate the inner and outer colour tracks would be decrypted by following the same steps as with the height track. The British spelling of "colour" seemed reasonable because the Rob Myers guy is a filthy Canadian, and CoinArtist seemed to have EU heritage, although I couldn't find anything definitive.
Interesting -- and that would make sense too. The binary pattern we *have* is:
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100110011100100001010110011010000001010010001010001001001010001001100000101010000101100100...
and the one that *would* say "thecolouriskeyfile" is:
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100110011100100000100111001011011101010010001010001001001010001001100000101010000101100100
Differences in bold. Maybe they got off somewhere in transcribing the pattern.
Re: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!
This thread seems pretty active again, so I figured I'd post some recent findings in hopes we can all solve this thing. ...
That's really interesting. I coded up my own version of this, and it's definitely there.
XOR'ing the key against the heights makes a lot of sense. Was there any rationale to the order you picked the flames? Or what led you to drop one of the flames to make it work (other than to make the math work out)?