Quote from: BlackHatCoiner on Today at 01:03:54 PM

Quote from: mynonce on Today at 10:49:18 AM

So we can say, that if you can sign with (1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W) then you have the private key of Satoshi's key.

Yeah. If you knew the private key of - 1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W - you'd be one step far from calculating this sought after Satoshi's address. It's simple elliptic curve maths.

If k₁G + k₂G = k₃G then (k₁ + k₂)G = k₃G → k₁ + k₂ = k₃.

Beautiful, isn't it?

Quote from: pooya87 on Today at 07:00:28 AM

... the idea is the same, you keep going backwards (t > h > g > i > r > W > C)...

That means the creator can't sign with the 'r' key, similar to the 1LZtnC7Ck37V9uLGGXFmaVkeaLyzFLvf6W case.

The creator starts with the signature address
17mZRodKy5ufNqJVsyKg1bEt81AnRkkh9L

then calculates the pubkeys for (t > h > g > i > r > W > C)
but for 'r' =
1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG
the creator doesn't have the private key but can show the public key and the address.

To prove the ownership of satoshi"s private key we would need 2 signatures:
1. for 17mZRodKy5ufNqJVsyKg1bEt81AnRkkh9L (it is posted)
2. for 1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG (not posted)

To the creator:
Post a signature for 1r7VRs5hwFNaqWSMdAGZVoQ7uQhsesRqG