Quote from: Denis_Hitov on August 22, 2023, 07:28:30 PM

Quote from: digaran on August 22, 2023, 07:08:31 PM

Anyone here knows how to divide a point by 3, 4, 5, 6, 7, 8, 9 and 10 and get a correct result?

Give me a few minutes, you will be amazed, I need to prepare the sample keys on laptop. Stay tuned.😉

Look forward to explanations! Good luck bro! Wink

Quote from: mcdouglasx on August 21, 2023, 07:20:38 PM

5- another form of successive subtraction

Code:

import secp256k1 as ice

target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub).hex()
print(res)

Tell me how to make each pub write from a new line, and not all in one line?

Code:

import secp256k1 as ice

target_public_key = "023d62d9d64a7164a2ae6f0561f7e8317e69b4a1ee61048fe768a1316b39b1d3a7"
target = ice.pub2upub(target_public_key)
num = 10 # number of times.
sustract= 1000 #amount to subtract each time.
sustract_pub= ice.scalar_multiplication(sustract)
res= ice.point_loop_subtraction(num, target, sustract_pub)
for t in range (num+1):
h= res[t*65:t*65+65]
data = open("loop-subtrac.txt","a")
data.write(str(h.hex())+"\n")
data.close()