Basic math and statistic told me this.
When you make 200 bets at 0,5% house edge, then you statistically will lose 1 bet, because 200 x 0,5% = 100% of 1 bet.
For example, when you make 201 bets at 0,5% house edge, then statistically you will win 100 bets and lose 101 bets.
The 1 bet you statistically will lose more after 201 bets, that is the house edge.
If the house edge is 0% and you make 200 bets, then statistically you will win 100 bets and lose 100 bets = no bet more lost = no house edge.
For example, when you make 205 bets at 5% house edge, then statistically you will win 100 bets and lose 105 bets.
Therefore, the number of bets you statistically will lose more than you win is the house edge!
The higher the house edge is, the higher is the number of bets you statistically will lose more than you win.
^thanks for the detailed reply. Since Blackjack we are talking about here, the outcome of the game depends on the players decision too which gives impact to the game.
The house edge set is when you play the game flawlessly using the blackjack table matrix but it will vary and increase significantly if you play differently from the strategy. This accusation is very hard to prove since the game needs to be checked individually for the decision making that he uses on a single game. If the game is dice then it’s easy to conclude with huge sample.
I played the game flawlessly and therefore should have experienced the advertised 0,5% house edge.
I offer to everyone to check my 180,900 bets if I played flawlessly!
If you make bets you win 42.22%, lose 49.1% and draw 8.49% .