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Showing 5 of 5 results by PROFIGROK
Post
Topic
Board Development & Technical Discussion
Topic OP
Number of kangaroos or speed of 1 kangaroo?
by
PROFIGROK
on 02/09/2025, 15:56:57 UTC
Hello. What's better? Number of kangaroos or speed of 1 kangaroo? It's better to launch 1 wild, 1 domesticated with a very fast speed. Is there a formula for calculation?
Post
Topic
Board Development & Technical Discussion
Re: P = A[X1, Y] - B[X2,Y]
by
PROFIGROK
on 28/08/2025, 09:05:18 UTC
Thank you for the detailed answer! Initially I have not A, but P, ​​for which I find A and B
Post
Topic
Board Development & Technical Discussion
Re: P = A[X1, Y] - B[X2,Y]
by
PROFIGROK
on 28/08/2025, 00:50:03 UTC
There are no keys to any point. I can only calculate suitable A and B for any point P
Post
Topic
Board Development & Technical Discussion
Re: P = A[X1, Y] - B[X2,Y]
by
PROFIGROK
on 27/08/2025, 17:43:19 UTC
Yes. But just when the only information you have is that the private key is anywhere between 1 and n - 1.

In other words: good luck finding the specific pair of points that add up to P (or one of its equivalent endos).
How to calculate the private key for my example?
Post
Topic
Board Development & Technical Discussion
Topic OP
P = A[X1, Y] - B[X2,Y]
by
PROFIGROK
on 27/08/2025, 10:15:15 UTC
Hi all.

Px = 80761252842007823267676923098838519533867178259061318285796836088556437370050
Py = 10738555717992617802285220494903845365923729217029449460443518382927240297340

Ax = 93560427823998350675410474831001446736200963751037120112392597322455167739793
Ay = 93848508593538492915520554344759249877309109996279289133143629759880647227979

Bx = 50213163450946219488224773860514757649033909603552708244598159315971281928720
By = 93848508593538492915520554344759249877309109996279289133143629759880647227979

A-B=P

Points A and B have a common Y coordinate. For each point P on the curve, there is a pair of points A and B such that A-B=P. Does this give us an advantage when computing the private key?

P.S. Sorry for my English Smiley